Find energy of each of the photons which (i) correspond to light of frequency 3×1015 Hz. (ii) have wavelength of 0.50 Å
We can use the following equations to calculate the energy of photons:
(i) Energy (E) of a photon is given by the equation E = hν, where h is the Planck's constant and ν is the frequency of the photon.
(ii) Energy (E) of a photon is given by the equation E = hc/λ, where h is the Planck's constant, c is the speed of light and λ is the wavelength of the photon.
(i) Given, frequency of light (ν) = 3 x 10^15 Hz
Using the first equation, we can calculate the energy of a photon as:
E = hν = (6.626 x 10^(-34) J s) x (3 x 10^15 Hz) = 1.99 x 10^(-18) J
Therefore, the energy of each photon is 1.99 x 10^(-18) J.
(ii) Given, wavelength of light (λ) = 0.50 Å = 0.50 x 10^(-10) m
Using the second equation, we can calculate the energy of a photon as:
E = hc/λ = (6.626 x 10^(-34) J s) x (3 x 10^8 m/s) / (0.50 x 10^(-10) m) = 3.97 x 10^(-17) J
Therefore, the energy of each photon is 3.97 x 10^(-17) J.
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